Let s = fa; b; c; d; e; f; gg be a collection of objects with benefit-weight values as follows: a: (12; 4); b: (10; 6); c: (8; 5); d: (11; 7); e: (14; 3); f : (7; 1); g: (9; 6). what is an optimal solution to the fractional knapsack problem for s assuming we have a sack that can hold objects with total weight 18? show your work.

50.6

step-by-step explanation:

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh