Write an equation in slope intercept form for the line that is parallel to y = x - 6 and that passes through the point (-5, -6)

y = x - 1

Step-by-step explanation:

First, determine your slope from the given equation y = x - 6

In slope intercept form: y = mx + b, the value for m is the slope.

By looking at "x", there is a coefficient of 1 and therefore 1 is the slope.

Since parallel lines have the same slope, use the slope 1 to rewrite a second eqaution using

the point-slope formula: y - y1 = m(x - x1) and the given point (-5, -6)

y - y1 = m(x - x1)

y - (-6) = 1 (x - (-5))        (Plug in values)

y + 6   = 1(x + 5)            (Distribute negatives)

y + 6   = 1x  + 5             (Distribute 1 to both terms in the parentheses)

 - 6             - 6              (Subtract 6 from both sides)

   y = 1x - 1 OR y = x - 1  

Check your work by plugging in the given point to your equation:

y = x - 1

-6 = -5 - 1                   (Plug in values)

-6 = -6

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1 1/7 hope i

step-by-step explanation:

8/7 = (1 * 7 + 1) / 7 = 1 + 1/7 = 1 1/7