In an effort to estimate the mean of amount spent per customer for dinner at a major lawrence restaurant, data were collected for a sample of 49 customers. assume a population standard deviation of $5. if the sample mean is $24.80, what is the 99% confidence interval for the population mean?

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine

Now by using z score table we find that  

The boundaries of the confidence interval are:

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

walter needs to make at least 5 more cookies but no more than 40. 5 ≥ x ≥ 40;

step-by-step explanation:

walter has to make a minimum of 20 cookies. he already has 15 cookies made, so he must make 5 more to meet the minimum.

the maximum amount of cookies he can make is 55. he already has 15, so he has to make no more than 40 more cookies to meet the maximum.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: