1. solve the inequality.
6x^2-x< 2
show your answer on a number line. state your answer in interval notation.

Your final answer is either

x≥-2   if your initial inequality was

6x+2≤2(5-x)

OR

x≤-2

if your initial inequality was

6x+2≥2(x-2)

Step-by-step explanation:

As shown you have an equality, not an inequality.

-6x+2=2(5-x)          distribute through parenthesis

-6x+2=2(5)+2(-x)

-6x+2=10-2x           add 2x to both sides

2x-6x+2=10-2x+2x

-4x+2=10                subtract 2 from both sides

-4x+2-2=10-2

-4x=8                      divide both sides by -4

-4x/(-4) = 8/(-4)

x = -2

With the ≥ or ≤ sign you would solve the exact same way

except for the point where when dividing both sides by

-4 requires you to reverse the inequality.

Your final answer is either

x≥-2   if your initial inequality was

6x+2≤2(5-x)

OR

x≤-2

if your initial inequality was

6x+2≥2(x-2)

step-by-step explanation:

my butt

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!