In a certain congressional district, it is known that 30% of the registered voters classify themselves as conservatives. if ten registered voters are selected at random from this district, what is the probability that two of them will be conservatives? (round your answer to four decimal places.)

0.2334

Step-by-step explanation:

We know that 30% are conservatives, so that is our proportion.

We define then,

p=0.30

n=0.7 (probability to not be conservative)

Our sample size (n) is 10.

So need to find if three of them are conservatives

This a typical binomial distribution

Here , (you can be either conservative or not conservative)

answer: the answer is 5/22

step-by-step explanation: if you subtract 17 from 22 the answer is 5 therefore the remainder of students are female

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: