Meredith invested $5,500 into an account that earned 5% interest per year. when she cashed out the investment to use it as a down payment for a new car, it was worth a total of $7,739.05.

which equation describes meredith's investment based on t, the number of years she kept the account open?

Step-by-step explanation:

Using I = PRT/100

where P = The principal amount invested = $5500

R = Rate of Interest =5%

T = Time (in years)

I = Interest = $7,739.05 - $5500 = $2239.05

Substituting the above values in the formula

I = PRT/100 becomes

2239.05 = 7,739.05 * 5 * t / 100 Multiply 100 to both sides

2239.05 * 100 = 100 * 7739.05 * 5 * t / 100

223905 = 7739.05 * 5 * t

223905 = 38695.25t

Divide both sides by 38695.25t

223905/38695.25 = t

5.786369 = t

T = 5.79 (approximated)

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

answer: 40.95

step-by-step explanation: