The diagonals of rectangle nopq intersect at point r. if or=3x-4 and np=5x+20, solve for x.

a.
2
b.
3
c.
12
d.
28

D. 28

Step-by-step explanation:

Please find the attachment.

We have been given that the diagonals of rectangle NOPQ intersect at point R. We are asked to find the value of x.

We will use diagonal property of rectangle, which states that diagonals of rectangle are equal and bisect each other.

Using diagonal property of rectangle, we can conclude that the segment NP is 2 times segment OR, so we can set an equation as:

Upon substituting the given expressions for both segments we will get,

Using distributive property we will get,

Subtracting 5x from both sides we will get,

Now, we will add 8 on both sides

Therefore, the value of x is 28 and option D is the correct choice.

left 3, up 4

step-by-step explanation:

just count the values of x & y of the vertex of the graph and see how many units in the x and y direction will get you from the f(x) graph to the f(x) graph

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer