6. you have a coin collection of nickels and dimes containing 63 coins. if you have $5.05, how may of each coin
do you have?

n + d = 20n = 20 - d

0.05n + 0.10d = 1.35

0.05(20 - d) + 0.10n = 1.35

1 - 0.05d + 0.10d = 1.35

-0.05d + 0.10d = 1.35 - 1

0.05d = 0.35

d = 0.35/0.05

d = 7 < 7 dimes

n + d = 20

n + 7 = 20

n = 20 - 7

n = 13 <=== 13 nickels

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x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer