What function describes a line with slope 4/3 and passing through the point (2,5) ?

The answer is: f(x) = 4/3x + 7/3

Step-by-step explanation:

Start with the point slope form of the equation:

y - y1 = m(x - x1)

y - 5 = 4/3(x - 2)

y - 5 = 4/3x - 8/3

y = 4/3x - 8/3 + 5

y = 4/3x - 8/3 + 15/3

y = 4/3x + 7/3

Replace y with f(x):

f(x) = 4/3x + 7/3

proof:

f(2) = 4/3 * 2 + 7/3

= 8/3 + 7/3 = 15/3 = 5

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