The sum of three numbers is -2. the sum of three times the first number, twice the second number, and the third number is nine. the difference between the second number and half the third is 10. find the numbers.

The numbers are 3, 5, -10.

Step-by-step explanation:

Let, the numbers are X, Y, Z.

Given, sum of the three numbers are -2.  

So, the equation is X + Y+ Z = -2 (i)

Again, for 2nd condition, the equation will be  

3X + 2Y + Z = 9   (ii)

Again, for the third condition, the equation will be

Y - (Z/2) = 10 (iii)

Multiplying the equation (i) by 3 and the equation (ii) by 1, we get

                     3X + 3Y+ 3Z = -6

                     3X + 2Y +  Z =  9

(Deduct)                  Y + 2Z = -15 (iv)  

Solving equation (iii) and (iv) we get,

                         Y - (Z/2) = 10

                         Y + 2Z   = -15

(Deduct)        -(Z/2) - 2Z = 25

or, (-Z-4Z)/2 = 25

or, -5Z = 25*2

or, Z = 50/(-5)

Therefore, Z = -10

Putting the value of Z into equation (iv) we get,

Y + 2*(-10) = -15

or, Y - 20 = -15

or, Y = 20 - 15

Therefore, Y = 5

Putting the value of Y and Z into equation (i) we get,

X + 5 + (-10) = -2

or, X + 5 - 10 = -2

or, X - 5 = -2

or, X = 5 - 2

Therefore, X = 3

So, the numbers are, X = 3; Y = 5; and Z = -10.

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's