Ine $l_1$ has equation $3x - 2y = 1$ and goes through $a = (-1, -2)$. line $l_2$ has equation $y = 1$ and meets line $l_1$ at point $b$. line $l_3$ has positive slope, goes through point $a$, and meets $l_2$ at point $c$. the area of $\triangle abc$ is $3$. what is the slope of $l_3$?

side xy = 10

sin(x) = 4/5

cos(x) = 3/5

tan(x) = 4/3

step-by-step explanation:

ans789

step-by-step explanation:

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.