Using the distance formula, classify the following triangle. a(7, -2) b(-4, 9) c(-3,-1)

A(7, -2) B(-4, 9) C(-3,-1)

AB² = (7 - -4)² + (9 - -2)² = 121 + 121 = 242

AC² = (7 - -3)² + (-2 - -1)² = 100 + 1 = 101

BC² = (-3 - -4)² + (9 - -1)² = 1 + 100 = 101

Since AC² + BC² ≠ AB² this isn't a right triangle

It is clearly an isosceles triangle because AC² = BC²

Isosceles

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