Mathematics, 07.11.2019 21:31 brisamauro27
The product of the slopes of two non vertical perpendicular lines is always .1 it is not possible for two perpendicular lines
to both have a positive slope because the product of two positives is positive. so for the product of the slopes to be 1, one
of the slopes must be positive and the other negative.
select the best answer from the choices provided
Answers: 2
Mathematics, 21.06.2019 16:30
Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane
Answers: 2
Mathematics, 21.06.2019 18:30
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Mathematics, 21.06.2019 18:30
Which value would be a solution for x in the inequality 47-4x< 7
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