How do i solve parallel and perpendicular lines

answer:

hope this < 3

step-by-step explanation:

step 1: find the slope of the line. to find the slope of the given line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y: the slope of the line 8x + 6y = 15 is m = –4/3. therefore, the slope of the line perpendicular to this line would have to be m = 3/4.

answer:

could you be a bit more specific?

step-by-step explanation:

parallel lines are two lines on the same plane that will never intersect. i like to remember this because the two l's in "parallel" are parallel.

perpendicular lines are lines that intersect at right angles.

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .