Find the equation of a line that runs through
(2,1) and is parallel to the line defined by
3x + y = -7.

Step-by-step explanation:

equation of a line

y - y1 = m(x -x1)

where (x1, y1) is a point on the line and m is the slope

since it is parallel to the line 3x + y = -7, put in y = mx + b form to find the slope

y = -3x - 7, therefore m = -3

y - 1 = -3(x - 2)

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

dd

step-by-step explanation:

dd