Mathematics, 08.11.2019 00:31 Dweath50

Aidan found 35 acorns at the park. he collected 5 times as many as daniel. he made a chart to compare the amount they each found. how do i write down an expression to show how to find the value of a.?

Answers: 3

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Answer from: Quest

820,000 is the answr

Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

Answer from: Quest

answer:

it is 28 degrees colder in detroit than philadelphia.

step-by-step explanation:

what number adds to 21

-7 + ? = 21

-7 + 28 = 21

hope it

Answer from: Quest

$3^{4x-5}=\left(\dfrac{1}{27}\right)^{2x+10}\\\\3^{4x-5}=\left(\dfrac{1}{3^3}\right)^{2x+10}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\3^{4x-5}=\left(3^{-3}\right)^{2x+10}\qquad\text{use}\ (a^n)^m=a^{n\cdot m}\\\\3^{4x-5}=3^{-3(2x+10)}\qquad\text{use distributive property}\\\\3^{4x-5}=3^{(-3)(2x)+(-3)(10)}\\\\3^{4x-5}=3^{-6x-30}\iff4x-5=-6x-30\qquad\text{add 5 to both sides}\\\\4x=-6x-25\qquad\text{add 6x to both sides}\\\\10x=-25\qquad\text{divide both sides by 10}\\\\\boxed{x=-2.5}$

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