In simultaneous equation, use the method of elimination solve for x and y

4x-3y=11
2x+5y=25

4x - 3y = 11

2x + 5y = 25

We'll double the second equation so it has the same x term as the first equation:

4x + 10y = 50

Then let's subtract this from the first equation"

-13 y = -39

Divide both sides by -13:

y = 3

Now let's substitute in one of the equations to get x:

2x = 25 - 5y = 25 - 5(3) = 10

x = 5

x=5, y=3

Check:

4(5) - 3(3) = 20 - 9 = 11, good

2(5) + 5(3) = 10 + 15 = 25, good