Members of the wide waters club pay
$105 per summer season, plus $9.50 each
time they rent a boat. nonmembers must
pay $14.75 each time they rent a boat.
how many times would a member and a
non-member have to rent a boat in order
to pay the same amount?

The number of times members and non-members will have to rent a boat in order to pay the same amount=20

Step-by-step explanation:

We can have two expressions to show the total cost paid by a member and non-member;

Total cost by member=Cost per summer season+cost per number of times they rent a boat×number of times they rent a boat

where;

Cost per summer season=$105

Cost per number of times they rent a boat=$9.50

Number of times they rent a boat=n

Replacing;

Total cost by a member=105+(9.5×n)=9.5 n+105equation 1

Total cost by a non-member=Cost per number of times they rent a boat×number of times they rent a boat

where;

Cost per number of times they rent a boat=$14.75

Number of times they rent a boat=n

Replacing;

Total cost by a non-member=(14.75×n)=14.75 nequation 2

To calculate the number of times they would have to rent a boat in order to pay the same amount, we equate equation 1 to equation 2

9.5 n+105=14.75 n

14.75 n-9.5 n=105

5.25 n=105

n=105/5.25

n=20

The number of times members and non-members will have to rent a boat in order to pay the same amount=20

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

idk wbu

step-by-step explanation: