Assume for the travel case discussed during the lecture, the size of the tank is 40 gallons with 2 gallons left in the tank instead at the border of city b. everything else is the same as what we have had in the case (see the course materials for this case). then, if we have enough budget, the maximum gas quantity which could be purchased for the whole trip (in b and c combined) is:

group of answer choices

none of other choices.

34 gallons

42 gallons

38 gallons

46 gallons

step-by-step explanation:

if x = 2 you have to find x to finish the problem

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

5

step-by-step explanation: