Amachine is used to fill containers with a liquid product. fill volume can be assumed to be normally distributed. a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.

(a) suppose that the manufacturer wants to be sure that the mean net contents exceeds 12 oz. what conclusions can be drawn from the data (use α= 0.01).

(b) construct a 95% two-sided confidence interval on the mean fill volume.

There is no statistical evidence at 1% level to accept that    the mean net contents exceeds 12 oz.

Step-by-step explanation:

Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.

We find mean = 11.015

Sample std deviation = 3.157

a)

(Right tailed test)

Mean difference /std error = test statistic

p value =0.174

Since p >0.01, our alpha, fail to reject H0

Conclusion:

There is no statistical evidence at 1% level to accept that    the mean net contents exceeds 12 oz.

the forst and 3rd

step-by-step explanation:

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3