The weekly amount of money spent on maintenance and repairs by a company was observed, over a long period of time, to be approximately normally distributed with mean $430 and standard deviation $10. how much should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05? (round your answer to the nearest cent.)

Budgeted amount is $446.44

Step-by-step explanation:

Given data:

mean  

standard deviation is given as

{ by using normal table or online calculator}

solving for x we have

x  = 446.44

Budgeted amount is $446.44

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.