Acable provider wants to contact customers in a particular telephone exchange to see how satisfied they are with the new digital tv service the company has provided. all numbers are in the 590 exchange, so there are 10 comma 000 possible numbers from 590- to 590-. if they select the numbers with equal probability: a) what distribution would they use to model the selection? b) what is the probability the number selected will be an odd number? c) what is the probability the number selected will end in 999?

a) Discrete Uniform Distribution

b) 0.5

c) 0.001

Step-by-step explanation:

a) What distribution would they use to model the selection?

Since each number has equal probability of being selected, they would be using a Discrete Uniform Distribution.

b) What is the probability the number selected will be an odd number?

Since there are 5,000 odd numbers between 0 and 9999

P(odd)=5,000/10,000 = ½ = 0.5

c) What is the probability the number selected will end in 999?

There are only 10 numbers ending in 999:

0999, 1999, 2999,...,9999

hence

P(number ends in 999)=10/10,000 = 1/1,000 = 0.001

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation:

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.