Which function has a period equal to half the period of the function in y = -3sin(x - 2π) + 2?

y = 3cos(2/3x - π) + 2
y = -3/2cos(2/3x - 2π) + 2
y = -3cos(2/3x - 2π) + 2
y = 3cos(3/4x - 2π) + 2

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

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step-by-step explanation:

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