Find the length of the legs of an
isosceles triangle if the legs
measure 5y-16 and 3y+10

5y-16=3y+10

5y-3y=10+16

2y=26

y=26/2

y=13

5×13-15=49

3×13+10=49

the length of the legs are 49 each

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

21

step-by-step explanation: