Which linear function has the greatest initial value and change.

Part A: Function C

Part B: Function B

Step-by-step explanation:

Part A:

Initial value of function A is the value of at .

Therefore, at

So, initial value of function A is 0.

Initial value of function B is given as:

Therefore, initial value of function B is -1.

Initial value of function C as seen in the graph is 2 because at .

Hence, on comparing the initial values of the three functions, function C has the greatest initial value.

Part B:

Rate of change of a function is given as:

For function A,

Therefore,

For function B, the coefficient of represents rate of change of the function.

Therefore, rate of change of function B is .

For function C, consider two points on the graph. Let the points be

Therefore, rate of change,

On comparing all the 3 rate of change, function B has the greatest rate of change of value 3.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!