Hury what is the range of the relation?
{(1, 2), (2, 4), (3, 2), (4, 4)}
a{2, 4, 6}

b{2, 4}

c{1, 2, 3, 4}

d{1, 2, 3, 4, 6}

Option B

The range of the relation is {2, 4}

Solution:

Given, function set is {(1, 2), (2, 4), (3, 2), (4, 4)}  

We have to find what is the range of the relation from given set of options.  

Now, we know that, in a function mapping set, the first elements of the brackets are from the domain set of the function and the second elements are from co – domain sets.

So, now, let us separate, the given function set as domain and co - domain  

Domain = {1, 2, 3, 4}

Co – domain = {2, 4}  

we wrote 2 and 4 only once, even when they are two times mapped in functions set as co –domain does not support duplicate elements.

So, co – domain = {2, 4}

Then, range will also be {2, 4} as we written the co – domain from function set directly, co –domain equals with range.

Hence, the range of the relation is {2, 4}.  Hence Option B is correct

30 feet

step-by-step explanation:

that would be 2 1/2 * 12

= 24 + 6

= 30 feet   (answer)

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages