In simplest radical form, what are the solutions to the quadratic eqaution 0=-3x^2-4x+5

Step-by-step explanation:

We have to find the solution of the quadratic single variable equation as given below:

- 3x² - 4x + 5 = 0 ..... (1)

The left-hand side can not be factorized.

So, apply The Sridhar Acharya Formula, which gives if ax² + bx + c = 0,the the solutions of the quadratic equation are

and,

So, from the equation (1), we can write  

and

⇒

⇒ (Answer)

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!