There are currently 17 frogs in a (large) pond. the frog population grows exponentially, tripling every 6 days. how long will it take (in days) for there to be 130 frogs in the pond? round your answer to the nearest hundredth.

t=11,11 days

Step-by-step explanation:

F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating ⇒ LnF=Kt+c,; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)), ⇒, so , now if F=130, t=? we have:

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form