He length of similar components produced by a company are approximated by a normaldistribution model with a mean of 5 cm and a standard deviation of 0.02 cm. if a component is chosen atrandoma)what is the probability that the length of this component is between 4.98 and 5.02?

0.6826894

Step-by-step explanation:

Given : The length of similar components produced by a company are approximated by a normal distribution model with a 5 cm and a 0.02 cm.

Let x be the random variable that represents the length of similar components produced by a company.

z-score :

For x= 4.98

For x= 5.02

By using the standard z-value table (right -tailed) , the probability that the length of this component is between 4.98 and 5.02 will be :_

Hence, the probability that the length of this component is between 4.98 and 5.02= 0.6826894

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

the answer is d on edge

step-by-step explanation: