An arrow is shot vertically upward at a rate of 170 feet per second from ground level.

*look at photo attached for the complete

t1= 1.1475 sec

t2=9.48 sec

Step-by-step explanation:

This question asking for the time when an object reach a specific height. I will explain what the formula stand for to make this easier.

h= height = 174feet

v0= initial velocity = 170 feet/s

t= time

h0= initial height= ground level = 0

The question have predetermined formula for the height, so we should use it instead of formula that involve gravity value.

h= -16 +v0t + h0t

174 feet = -16 + 170 feet/s x t + 0 x t

-16 + 170 feet/s x t  - 174 feet = 0

8 - 85 feet/s x t  + 87 feet = 0

This equation will be hard to solve since its value in fraction, so lets use the quadratic formula

t1=

t1= 1.1475

t2=

t2=9.48

i dony know

step-by-step explanation:

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.