Atraining field is formed by joining a rectangle and two semicircles, as shown below. the rectangle is 96m long and 74m wide.
find the area of the training field. use the value 3,14 for pie , and do not round your answer. be sure to include the correct unit in your answer.

Step-by-step explanation:

The width of rectangle is the diameter of the semi-circle part

Area of one semicircle is given by

Total area of semi circle will be

Substituting 74 m for d and as 3.14 we obtain

Total area semi-circle=

Area of rectangle is given by the product of length and width

Rectangular area=

Total area of rectangular and semi-circles will be

Therefore, area of training field is

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