You and a friend are going bowling. renting shoes and the first game of bowling costs $7.50 for each person. if each
game after the first costs $2.50 per person, write a formula for the cost, c, per person after 9 games.

a) cg= $7.50 + (n - 1) . $2.50

b) cg= $2.50 + (n - 1). $7.50

c) cg= $5.00 + (n - 1). $7.50

d) cg= $5.00 + (n - 1) . $2.50

only answer if you know it!

A) The cost of playing n games of bowling is C(n) = $7.50 + (n - 1) . $2.50

Step-by-step explanation:

The cost of first game of bowling  for each person  = $7.50

Cost after first game per person = $2.50

Total  number of games played = n

According to the question:

Total cost of playing n  games  =  Cost of first game +  {(n-1) x  Cost after first game}

or, C(n) = $7.50 + (n-1)$2.50

Hence, the cost of playing n games of bowling is

C(n) = $7.50 + (n - 1) . $2.50

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a