69 !

what are the solutions of the following system?
{x² + y² = 25
{ 2x+y=-5

a(0,-5) and (-5,5)
b (0,-5) and (5, -15)
c(0, -5) and (-4,3)
d(0,-5) and (4, -13)

C)  The solution for the given system of equations are A(0,-5) and B(-4,3)

Step-by-step explanation:

The given system of equation are :

from equation 2, we get   y = -5 - 2x .

Put the above value of y in the equation (1).

We get:

By ALGEBRAIC IDENTITY:

or,

or,

⇒ x = 0 or,   x  = -20/5 = -4

So, the possible values for x are: x  = 0 or  x  = -4

If x  = 0, y = -5-2x = -5-2(0) = -5

and if x = -4, y = -5 -2(-4)   = -5 + 8  = 3

Hence, the solution for the given system of equations are A(0,-5) and B(-4,3)

add an image

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl