Abox has a volume of 128 feet3. the length is twice the width and the height is the same as the width. what are the dimensions of the box?

Let the width of the box = X

The height would also be X

The length would be 2X

Volume = L x W x H

128 = X * X  *2x

Simplify:

128 = x^2 * 2x

128 = x^3 * 2

Divide both sides by 2:

x^3 = 64

Take the cubic root of both sides:

X = 4

The width = 4 feet

The height = 4 feet

The length = 8 feet.

W = 4 ft     H=4 ft    L=8 ft

Step-by-step explanation:

Suppose the box is a rectangular box and its volume is 128 cubic feet

W: Wide L: Length H:Height

H=2W    

H=W

Box volume: H*W*L=2W*W*W=2W³

2W³ = 128

W³ = 64

W = 4 ft     H=4 ft    L=8 ft

∠cbe and ∠deb are same-side interior angles.

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step-by-step explanation: