What is the nth term of the geometric sequence that has a common ratio of 6 and 24 as its third term?

The nth term of the series is

Step-by-step explanation:

Given: Third term = 24 and r = 6

We are given third term and common ratio of geometric series.

Formula:

For third term, n=3 and r=6

We need to find nth term of the series

Hence, The nth term of the series is

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Step-by-step explanation:

2/3 * 6^(n-1)

Step-by-step explanation:

The formula is a*r^(n-1)

so if the 3rd term (n=3) is 24 and the common ratio, r, is 6

24 = a* 6^(3-1)

So we are looking for a, yeah. 3-1 is 2 so 6^2 is 36. Simplify

24/36 = a

2/3 = a

Then just use that to write formula of the sequence

gdp is the best phrase!

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°