Use technology to construct the confidence intervals for the population variance sigmaσsquared2 and the population standard deviation sigmaσ. assume the sample is taken from a normally distributed population. cequals=0.99, sequals=35, nequals=19the confidence interval for the population variance is ( nothing, nothing).

(593.44, 3519.67).

Step-by-step explanation:

As per given , we have

Confidence level :

Significance level :

Sample size : n= 19

Sample standard deviation : s= 35

Using chi-square distribution table , the critical values are:

Now, the Confidence interval for the population variance is given by :-

Hence, the confidence interval for the population variance is (593.44, 3519.67).

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt