Given the following chemical reaction:

2 o2 + ch4 → co2 + 2 h2o

in the reaction of 6 moles of ch4 with excess oxygen, how many moles of water could be produced?

6
c
12.01
carbon

1
h
1.01
hydrogen

8
o
16.00
oxygen

a.) 4
b.) 6
c.) 8
d.) 12

The answer to your question is 12 moles of water.

Step-by-step explanation:

Reaction

                            2 O₂   +   CH₄     ⇒     CO₂    +   2 H₂O

If Oxygen is in excess, then the limiting reactant is methane and we calculate the moles of water produced considering the moles of methane.

                          1 mol of methane  2 moles of water

                           6 moles of methane   x

                           x = (6 x 2) / 1

                           x = 12 moles of water

answer: 1722

step-by-step explanation:

given: the mass of saturn=

the mass of mercury=

the number of times the mass of saturn is greater than the mass of mercury

hence, the mass of saturn is 1722 times greater than the mass of mercury.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %