Martin bought 2 kilograms of bananas and 3 kilograms of oranges for $16.50. if oranges were 0.50 cents a kilogram more than the bananas, how much did the oranges and bananas cost per kilogram?

Bananas  = $3.6/ kg

Oranges  = $3.1/ kg

Step-by-step explanation:

Let represent Bananas by B and Oranges by O:

According to given conditions:

2B + 3O = $16.50  eq1

O + 0.50 = B eq2

By taking eq2:

O = B - 0.50 eq3

Now putting value of O in eq1 we get:

2B + 3(B - 0.50) = $16.50

By simplifying we get:

2B + 3B - 1.5 =  $16.50

5B = $(16.50 + 1.5)

5B = $18

B = $3.6

Putting value of B in eq3

O = $3.6 -0.50

O = $3.1

So the cost for Bananas And Oranges per kilogram are:

Bananas = B = $3.6

Oranges = O = $3.1

I hope it will help you!

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.