What is the missing step in the proof? a. statement: ∠gac and ∠gab are supplementary. reason: linear pair theorem b. statement: ∠afe ≅ ∠afd reason: transitive property of equality c. statement: ∠gac ≅ ∠baf reason: vertical angles theorem d. statement: ∠gac and ∠afd are supplementary. reason: linear pair theorem

answer: the common difference is -0.10

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

a is the right answer