Anationwide careerbuilder survey was conducted regarding the job hunting experience. from the survey, it was learned that 26% of workers have had a bad experience as a job applicant eighty-two percent of workers expect to hear back from a company when they apply for a job. suppose that 90% of workers who have had a bad experience as a job applicant expect to hear back from a company when they apply for a job. based on these results, if a worker hunting for a job is randomly selected, a. what is the probability that the worker expects to hear back from a company when they apply for a job and has had a bad experience as a job applicant? b. what is the probability that the worker expects to hear back from a company when they apply for a job and has not had a bad experience as a job applicant? c. what is the probability that the worker does not expect to hear back from a company when they apply for a job and has had a bad experience as a job applicant? d. what is the probability that the worker does not expect to hear back from a company when they apply for a job and has not had a bad experience as a job applicant?

1/800 is the right answer

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

step-by-step explanation:

the answer is 128

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺