The length of a rectangle is 4 cm greater than its width. if the area of the rectangle is 108 cm^2 what are the approximate dimensions of the rectangle?

Step-by-step explanation:

I think some values are incorrect. You could always ask your teacher.

Edit:

In case of approximate dimensions, the answer is bound to be in fraction form.

So,

The area of a rectangal is lxb.

If the length is 4cm more than the breadth, the required equation would be:

x(x+4).

So, area= lxb

108= x(x+4)

108= x^2 + 4x.

108÷4 = x^2

27 =x^2

x= √27

x+4=√27+4

answer: plz put a pic in so i can answer it

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.