Solve −x16+1≥−5x2, for x without multiplying by a negative number. then, solve by multiplying through by −16.

−1.13348172≤x≤1.13348172

Step-by-step explanation:

For this problem

Add −5x2 to both sides of the inequality.

−x16 + 1 + 5x2≥0

Convert inequality to an equation.

−x16 + 1 + 5x2 = 0

Factor −x16 + 1 + 5x2

Set the factor equal to 00.

x16−5x2−1 = 0

x≈ − 1.13348172,1.13348172

so,

x≤ − 1,13348172

−1.13348172≤x≤1.13348172

x≥1.13348172

−1.13348172≤x≤1.13348172

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

maybe i can