Achemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. the premium antifreeze solution contains 80% pure antifreeze. the company wants to obtain 160 gallons of a mixture that contains 40% pure antifreeze. how many gallons of water and how many gallons of the premium antifreeze solution must be mixed?

water: 80 gallons

premium antifreeze : 80 gallon s

Step-by-step explanation:

Final solution is 160 gallon of 40% antifreeze

volume of pure antifreeze = 40% of 160 gallon =0.4*160= 64 gallons

Let say we mix x gallons water and y gallons premium antifreeze

amount of pure antifreeze = 80% of y

80*y/100 = 64

y = 80 gallons

x+y = 160 gallon s

x = 160-80=80 gallons

Therefore, you require

water: 80 gallons

premium antifreeze : 80 gallon s

associative property of multiplication

c

step-by-step explanation: