Abox with 3 metal balls weighs 1840 kg.
each metal ball weighs thrice as heavy as the box.
how much does a box with 1 metal ball weigh?

weight = 736 kg

Step-by-step explanation:

Let ball be denoted by b and box by x

Given that:

3b + x = 1840kg eq1

According to given scenario:

each ball is thrice heavy than box So,

b = 3x eq2

Putting value of b in eq1

3 (3x) + x = 1840 kg

9x + x = 1840 kg

10x = 1840 kg

Dividing both sides by 10

x = 184 kg

Now finding weight of betal ball

Putting value of x in eq 2

b = 3 (184)

b = 552 kg

So the weight of one ball and box is:

weight = ball + box

weight = 552kg + 184 kg

weight = 736 kg

i hope it will help you!

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

what are the statments

step-by-step explanation: