7. a ball is thrown into the air from a height of 6 feet. the function that models
this situation is h(t) = –16t2 + 640 + 6, where tis measured in seconds and
h is the height. what is the maximum height of the ball and how long did it
take the ball to reach the maximum height?

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

what? that isnt a question

step-by-step explanation: