If an object is projected upward with an initial velocity of 48 feet per second, at what times will it reach a height of 32 feet above the ground. given h(t)=vt - 16t^2

t = 1s and t = 2s

Step-by-step explanation:

We have the equation

where

and

Thus, the equation now becomes:

To solve, we must first equal the quadratic equation to zero

Solve this equation for t using the general formula for a quadratic equation

but in this case intead of x we have t.

Where a is the coefficient of the quadratic term.

b is the coefficient of the linear term, and c the independent term.

And now we substitute these values in the general formula:

Now, we are going to have two values for t due to the +- sign. Using the negative sign:

And using the positive sign:

At times t = 1s and t = 2s the object will it reach a height of 32 feet above the ground.

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