The voltage v in a simple electrical circuit is slowly decreasing as the battery wears out. the resistance r is slowly increasing as the resistor heats up. use ohm's law, v = ir, to find how the current i is changing at the moment when r = 465? , i = 0.09a, dv/dt =-0.03v/s, and dr/dt = 0.03? /s. (round your answer to six decimal places.)

The current I is changing at -0.000012.

Step-by-step explanation:

Given : The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR

To find : How the current I is changing at the moment.

Solution :

We have given,

R = 465\ ohm, I = 0.09A, and

Using Ohm's law, we find V

Re-write ohm's law in terms of I,

Derivate w.r.t to t,

Substitute the values given,

The current I is changing at -0.000012.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.