Twice one number added to another numbers 18. if the second number id equal to 12 less than 4 times the first number, find the two numbers

The Answer is: The first number is 5 and the second one is 8.

Step-by-step explanation:

Let f = first number and s = second number

Twice the first number added to the second number is 18:

2f + s = 18

The second number is equal to 4 times the first number minus 12:

s = 4f - 12

Substitute:

2f + (4f - 12) = 18

6f - 12 = 18

6f = 18 + 12

6f = 30

f = 5, is the first number.

Solve for the 2nd number:

s = 4(5) - 12 = 20 - 12 = 8, is the second number.

Proof:

2f + s = 18

2(5) + 8 = 18

18 = 18

Hope this helps! Have an Awesome Day! :-)

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

2

step-by-step explanation: