Two-digit natural numbers are formed, with replacement, from the digits 0 through 9.

how many two-digit odd numbers are possible?

50 two-digit odd numbers are formed

Step-by-step explanation:

From the digits from 0 to 9 to get two -digit odd numbers you will need to pair numbers from

0 to 9 as the first digit of the numbers = 10 possible numbers

and also you will need to pair the first digits with an odd number as the second digit .

to get the odd numbers as second digits you will need to pick from

 1 , 3 , 5 ,7 and 9 = 5 possible numbers.

zero is  considered in the first digit because zero can start a two digit natural number and zero is not considered in the second digit because zero is an even number.

to get the possible two -digit number you will have to multiple the possible numbers for the first digits with the possible numbers for the second digits which is =

        10 * 5 = 50 hence there will be 50 possible two-digit  odd numbers.

too hard the other guy did it

step-by-step explanation:

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation: