Write an equation of a line that is perpendicular to the line 2x-3y+15=0

Step-by-step explanation:

The equation of the given straight line is 2x - 3y + 15 = 0.

Now, we can express the equation as 3y = 2x + 15

⇒ ..........(1)

The equation is in slope-intercept form and the slope is =

Therefore, the equation of a straight line which is perpendicular to (1) is  

{Where c is any constant}

{Since, the product of slopes of two perpendicular straight lines is -1}

Now, putting c = 1, we get the equation as . (Answer)

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the answer on ed. is:

c. "the graph of f(x) has exactly two x-intercepts."

hope i could someone! : )